What is the inverse of x/(sqrt(x^2+1)) ?

The inverse of x/(sqrt(x^2+1)) is sqrt(-(x^2)/(x^2-1)),-sqrt(-(x^2)/(x^2-1))

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inverse of x/(sqrt(x^2+1))

inverse

\frac{x}{x ^{2} + 1}

- \frac{x ^{2}}{x ^{2} - 1}, - - \frac{x ^{2}}{x ^{2} - 1}

Solution steps

y = \frac{x}{x ^{2} + 1}

Replace

x

with

y

x = \frac{y}{y ^{2} + 1}

Solve for

y, x = \frac{y}{y ^{2} + 1}

- \frac{x ^{2}}{x ^{2} - 1}, - - \frac{x ^{2}}{x ^{2} - 1}

f (x) = \frac{3 x + 8}{5}

f (x) = \frac{1}{5} x - 7

f (x) = - 10 x + 5

f (x) = \frac{2 x - 5}{x + 7}

\frac{x}{- x + 1}

What is the inverse of x/(sqrt(x^2+1)) ?
The inverse of x/(sqrt(x^2+1)) is sqrt(-(x^2)/(x^2-1)),-sqrt(-(x^2)/(x^2-1))