What is the inverse of f(x)=2cos(4x-pi) ?

The inverse of f(x)=2cos(4x-pi) is (arccos(x/2)+pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2cos(4x-pi)

inverse

f (x) = 2 cos (4 x - π)

\frac{arccos ( \frac{x}{2} ) + π}{4}

Solution steps

Solve for

cos (4 x - π), y = 2 cos (4 x - π)

cos (4 x - π) = \frac{y}{2}

cos (a) = b \Rightarrow a = arccos (b)

4 x - π = arccos (\frac{y}{2})

Solve for

x, 4 x - π = arccos (\frac{y}{2})

\frac{arccos ( \frac{y}{2} ) + π}{4}

Substitute

y = x

\frac{arccos ( \frac{x}{2} ) + π}{4}

f (x) = - 7 x - 4

f (x) = \frac{x - 2}{6}

f (x) = \frac{e ^{x} - 1}{e ^{x} + 1}

f (x) = - \frac{4}{5} x + 12

f (x) = \frac{5 - 3 ^{x}}{2}

What is the inverse of f(x)=2cos(4x-pi) ?
The inverse of f(x)=2cos(4x-pi) is (arccos(x/2)+pi)/4