What is the inverse of f(x)=(x+3)^2-4 ?

The inverse of f(x)=(x+3)^2-4 is sqrt(x+4)-3,-sqrt(x+4)-3

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inverse of f(x)=(x+3)^2-4

inverse

f (x) = (x + 3)^{2} - 4

x + 4 - 3, - x + 4 - 3

Solution steps

y = (x + 3)^{2} - 4

Replace

x

with

y

x = (y + 3)^{2} - 4

Solve for

y, x = (y + 3)^{2} - 4

x + 4 - 3, - x + 4 - 3

cosh (x)

f (x) = \frac{3 x - 1}{2}

f (x) = 5 x + 1

f (x) = - \frac{6 x}{7}

f (x) = 3^{x + 1} + 4

What is the inverse of f(x)=(x+3)^2-4 ?
The inverse of f(x)=(x+3)^2-4 is sqrt(x+4)-3,-sqrt(x+4)-3