What is the inverse of s/(s^2+4s+5) ?

The inverse of s/(s^2+4s+5) is (-4s+1+sqrt(-4s^2-8s+1))/(2s),(-4s+1-sqrt(-4s^2-8s+1))/(2s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of s/(s^2+4s+5)

inverse

\frac{s}{s ^{2} + 4 s + 5}

\frac{- 4 s + 1 + - 4 s ^{2} - 8 s + 1}{2 s}, \frac{- 4 s + 1 - - 4 s ^{2} - 8 s + 1}{2 s}

Solution steps

y = \frac{s}{s ^{2} + 4 s + 5}

Replace

s

with

y

s = \frac{y}{y ^{2} + 4 y + 5}

Solve for

y, s = \frac{y}{y ^{2} + 4 y + 5}

\frac{- 4 s + 1 + - 4 s ^{2} - 8 s + 1}{2 s}, \frac{- 4 s + 1 - - 4 s ^{2} - 8 s + 1}{2 s}

f (x) = (\frac{1}{2})^{x + 1} - 2

f (x) = - 2 (x + 3)^{3}

f (x) = 2 x + 5 + 4

\frac{2}{x - 3}

f (x) = \frac{1}{7} x - \frac{3}{7}

What is the inverse of s/(s^2+4s+5) ?
The inverse of s/(s^2+4s+5) is (-4s+1+sqrt(-4s^2-8s+1))/(2s),(-4s+1-sqrt(-4s^2-8s+1))/(2s)