What is the inverse of f(x)=log_{10}(2x+3) ?

The inverse of f(x)=log_{10}(2x+3) is (10^x-3)/2

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inverse of f(x)=log_{10}(2x+3)

inverse

f (x) = lo g_{10} (2 x + 3)

\frac{1 0 ^{x} - 3}{2}

Solution steps

y = lo g_{10} (2 x + 3)

Replace

x

with

y

x = lo g_{10} (2 y + 3)

Solve for

y, x = lo g_{10} (2 y + 3)

\frac{1 0 ^{x} - 3}{2}

f (x) = \frac{5 x + 2}{x - 5}

f (x) = \frac{7 x + 6}{x - 5}

f (x) = 7 (x^{\frac{1}{5}} - 10)

f (x) = - \frac{1}{2} x + 9

f (x) = (c + 1)^{3} - 1

What is the inverse of f(x)=log_{10}(2x+3) ?
The inverse of f(x)=log_{10}(2x+3) is (10^x-3)/2