What is the inverse of (x^2-4)^{5/3} ?

The inverse of (x^2-4)^{5/3} is sqrt(x^{3/5)+4},-sqrt(x^{3/5)+4}

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inverse of (x^2-4)^{5/3}

inverse

(x^{2} - 4)^{\frac{5}{3}}

x^{\frac{3}{5}} + 4, - x^{\frac{3}{5}} + 4

Solution steps

y = (x^{2} - 4)^{\frac{5}{3}}

Replace

x

with

y

x = (y^{2} - 4)^{\frac{5}{3}}

Solve for

y, x = (y^{2} - 4)^{\frac{5}{3}}

x^{\frac{3}{5}} + 4, - x^{\frac{3}{5}} + 4

f (x) = \frac{4}{3} x - 16

f (x) = e^{x} - 9

f (x) = 12 x - 1

4 + x - 2

f (x) = - \frac{3}{x + 4}

What is the inverse of (x^2-4)^{5/3} ?
The inverse of (x^2-4)^{5/3} is sqrt(x^{3/5)+4},-sqrt(x^{3/5)+4}