What is the inverse of f(x)=x^2+x-6,x>=-1/2 ?

The inverse of f(x)=x^2+x-6,x>=-1/2 is (-1+sqrt(4x+25))/2 ,(-1-sqrt(4x+25))/2

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inverse of f(x)=x^2+x-6,x>=-1/2

inverse

f (x) = x^{2} + x - 6, x \geq - \frac{1}{2}

\frac{- 1 + 4 x + 25}{2}, \frac{- 1 - 4 x + 25}{2}

Solution steps

y = x^{2} + x - 6

Replace

x

with

y

x = y^{2} + y - 6

Solve for

y, x = y^{2} + y - 6

\frac{- 1 + 4 x + 25}{2}, \frac{- 1 - 4 x + 25}{2}

f (x) = e^{x} + 1

f (x) = \frac{5 x}{3 x + 1}

f (x) = \frac{2 - x}{6 - x}

f (x) = 9 x - 1

y = 2 x + 6

What is the inverse of f(x)=x^2+x-6,x>=-1/2 ?
The inverse of f(x)=x^2+x-6,x>=-1/2 is (-1+sqrt(4x+25))/2 ,(-1-sqrt(4x+25))/2