What is the inverse of g(x)=4(x-1)^2 ?

The inverse of g(x)=4(x-1)^2 is (sqrt(x))/2+1,-(sqrt(x))/2+1

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inverse of g(x)=4(x-1)^2

inverse

g (x) = 4 (x - 1)^{2}

\frac{x}{2} + 1, - \frac{x}{2} + 1

Solution steps

y = 4 (x - 1)^{2}

Replace

x

with

y

x = 4 (y - 1)^{2}

Solve for

y, x = 4 (y - 1)^{2}

\frac{x}{2} + 1, - \frac{x}{2} + 1

f (x) = 10 x + 3

f (x) = \frac{2 x}{x + 4}

arctan (- 1)

\frac{x + 3}{x - 4}

f (x) = \frac{x}{3} + 5

What is the inverse of g(x)=4(x-1)^2 ?
The inverse of g(x)=4(x-1)^2 is (sqrt(x))/2+1,-(sqrt(x))/2+1