What is the inverse of f(x)=3+2x+x^2 ?

The inverse of f(x)=3+2x+x^2 is -1+sqrt(x-2),-sqrt(x-2)-1

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inverse of f(x)=3+2x+x^2

inverse

f (x) = 3 + 2 x + x^{2}

- 1 + x - 2, - x - 2 - 1

Solution steps

y = 3 + 2 x + x^{2}

Replace

x

with

y

x = 3 + 2 y + y^{2}

Solve for

y, x = 3 + 2 y + y^{2}

- 1 + x - 2, - x - 2 - 1

f (x) = - \frac{4 x}{7}

f (x) = 2 ln (\frac{x + 3}{5})

f (x) = (x^{2} + 5 x)^{\frac{1}{2}}

e^{x + 1}

f (x) = \frac{x ^{7}}{8} + 8

What is the inverse of f(x)=3+2x+x^2 ?
The inverse of f(x)=3+2x+x^2 is -1+sqrt(x-2),-sqrt(x-2)-1