What is the inverse of f(x)=3x^2+2,x>= 0 ?

The inverse of f(x)=3x^2+2,x>= 0 is sqrt((x-2)/3),-sqrt((x-2)/3)

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inverse of f(x)=3x^2+2,x>= 0

inverse

f (x) = 3 x^{2} + 2, x \geq 0

\frac{x - 2}{3}, - \frac{x - 2}{3}

Solution steps

y = 3 x^{2} + 2

Replace

x

with

y

x = 3 y^{2} + 2

Solve for

y, x = 3 y^{2} + 2

\frac{x - 2}{3}, - \frac{x - 2}{3}

f (x) = e^{x - 5}

y = arcsec (x)

f (x) = - \frac{3}{x + 1} - 3

\frac{x - 1}{2 x + 3}

f (x) = \frac{1}{8} x - \frac{5}{8}

What is the inverse of f(x)=3x^2+2,x>= 0 ?
The inverse of f(x)=3x^2+2,x>= 0 is sqrt((x-2)/3),-sqrt((x-2)/3)