What is the inverse of f(x)=\sqrt[3]{x+4}-5 ?

The inverse of f(x)=\sqrt[3]{x+4}-5 is x^3+15x^2+75x+121

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inverse of f(x)=\sqrt[3]{x+4}-5

inverse

x^{3} + 15 x^{2} + 75 x + 121

Solution steps

Replace

x

with

y

Solve for

x^{3} + 15 x^{2} + 75 x + 121

f (x) = \frac{2 x - 1}{3 - 4 x}

f (x) = (3 x^{3} + 2)^{\frac{1}{5}}

f (x) = \frac{2 x + 1}{x - 2}

f (x) = \frac{( 3 - 2 x )}{3 x + 2}

What is the inverse of f(x)=\sqrt[3]{x+4}-5 ?
The inverse of f(x)=\sqrt[3]{x+4}-5 is x^3+15x^2+75x+121