What is the inverse of f(x)=((bx+3))/(3x-7) ?

The inverse of f(x)=((bx+3))/(3x-7) is (3+7x)/(3x-b)

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inverse of f(x)=((bx+3))/(3x-7)

inverse

f (x) = \frac{( b x + 3 )}{3 x - 7}

\frac{3 + 7 x}{3 x - b}

Solution steps

y = \frac{b x + 3}{3 x - 7}

Replace

x

with

y

x = \frac{b y + 3}{3 y - 7}

Solve for

y, x = \frac{b y + 3}{3 y - 7}

\frac{3 + 7 x}{3 x - b}

f (x) = 6 x^{5} - 1

3 x + 8

f (x) = (x + 7)^{3} - 1

f (x) = \frac{x + 10}{9 x - 1}

f (n) = 2 (n - 2)^{3}

What is the inverse of f(x)=((bx+3))/(3x-7) ?
The inverse of f(x)=((bx+3))/(3x-7) is (3+7x)/(3x-b)