What is the inverse of f(x)=-x^2+3x-2 ?

The inverse of f(x)=-x^2+3x-2 is -(-3+sqrt(-4x+1))/2 ,-(-3-sqrt(-4x+1))/2

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inverse of f(x)=-x^2+3x-2

inverse

f (x) = - x^{2} + 3 x - 2

- \frac{- 3 + - 4 x + 1}{2}, - \frac{- 3 - - 4 x + 1}{2}

Solution steps

y = - x^{2} + 3 x - 2

Replace

x

with

y

x = - y^{2} + 3 y - 2

Solve for

y, x = - y^{2} + 3 y - 2

- \frac{- 3 + - 4 x + 1}{2}, - \frac{- 3 - - 4 x + 1}{2}

y = 10 x - 2

f (x) = \frac{( x - 5 )}{2}

f (x) = (4 x + 8)^{3} - 16

f (x) = 2 - \frac{3}{x}

What is the inverse of f(x)=-x^2+3x-2 ?
The inverse of f(x)=-x^2+3x-2 is -(-3+sqrt(-4x+1))/2 ,-(-3-sqrt(-4x+1))/2