What is the inverse of f(x)= 7/(sqrt(x+3)) ?

The inverse of f(x)= 7/(sqrt(x+3)) is (49)/(x^2)-3

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inverse of f(x)= 7/(sqrt(x+3))

inverse

f (x) = \frac{7}{x + 3}

\frac{49}{x ^{2}} - 3

Solution steps

y = \frac{7}{x + 3}

Replace

x

with

y

x = \frac{7}{y + 3}

Solve for

y, x = \frac{7}{y + 3}

\frac{49}{x ^{2}} - 3

f (x) = 7 x^{\frac{1}{5}} + 6

f (x) = 3 x^{2} - 6

f (x) = x^{7} + 2

g (x) = 7 x + 3

f (x) = 4 x^{3} + 1

What is the inverse of f(x)= 7/(sqrt(x+3)) ?
The inverse of f(x)= 7/(sqrt(x+3)) is (49)/(x^2)-3