What is the inverse of f(x)=-2(x-3)^2-2 ?

The inverse of f(x)=-2(x-3)^2-2 is sqrt(-(x+2)/2)+3,-sqrt(-(x+2)/2)+3

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inverse of f(x)=-2(x-3)^2-2

inverse

f (x) = - 2 (x - 3)^{2} - 2

- \frac{x + 2}{2} + 3, - - \frac{x + 2}{2} + 3

Solution steps

y = - 2 (x - 3)^{2} - 2

Replace

x

with

y

x = - 2 (y - 3)^{2} - 2

Solve for

y, x = - 2 (y - 3)^{2} - 2

- \frac{x + 2}{2} + 3, - - \frac{x + 2}{2} + 3

tan (3)

f (x) = x^{2} + b x + 1

f (x) = \frac{5 x + 2}{x - 9}

f (x) = \frac{3 - x}{7}

f (x) = \frac{3}{x + 5}

What is the inverse of f(x)=-2(x-3)^2-2 ?
The inverse of f(x)=-2(x-3)^2-2 is sqrt(-(x+2)/2)+3,-sqrt(-(x+2)/2)+3