What is the inverse of f(x)=2sqrt(x-3)+1 ?

The inverse of f(x)=2sqrt(x-3)+1 is (x^2+1)/4-x/2+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2sqrt(x-3)+1

inverse

f (x) = 2 x - 3 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 3

Solution steps

y = 2 x - 3 + 1

Replace

x

with

y

x = 2 y - 3 + 1

Solve for

y, x = 2 y - 3 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 3

y = x^{2} + 1, x > 0

f (x) = (x - 3)^{4}

f (x) = \frac{3 x}{4 x - 3}

f (x) = \frac{x ^{5} - 3}{2}

What is the inverse of f(x)=2sqrt(x-3)+1 ?
The inverse of f(x)=2sqrt(x-3)+1 is (x^2+1)/4-x/2+3