What is the inverse of f(x)=3x^2-9 ?

The inverse of f(x)=3x^2-9 is sqrt((x+9)/3),-sqrt((x+9)/3)

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inverse of f(x)=3x^2-9

inverse

f (x) = 3 x^{2} - 9

\frac{x + 9}{3}, - \frac{x + 9}{3}

Solution steps

y = 3 x^{2} - 9

Replace

x

with

y

x = 3 y^{2} - 9

Solve for

y, x = 3 y^{2} - 9

\frac{x + 9}{3}, - \frac{x + 9}{3}

f (x) = \frac{3 x + 8}{4 x + 5}

4 x + 12

f (x) = \frac{1}{2} x^{2} - x - 3

f (x) = 8 x^{3} - 2

f (x) = \frac{x ^{3} + 8}{7}

What is the inverse of f(x)=3x^2-9 ?
The inverse of f(x)=3x^2-9 is sqrt((x+9)/3),-sqrt((x+9)/3)