What is the inverse of f(x)=((x-1)^3)/2-3 ?

The inverse of f(x)=((x-1)^3)/2-3 is \sqrt[3]{2x+6}+1

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inverse of f(x)=((x-1)^3)/2-3

inverse

f (x) = \frac{( x - 1 ) ^{3}}{2} - 3

Solution steps

y = \frac{( x - 1 ) ^{3}}{2} - 3

Replace

x

with

y

x = \frac{( y - 1 ) ^{3}}{2} - 3

Solve for

y, x = \frac{( y - 1 ) ^{3}}{2} - 3

f (x) = 5 x + x + 26

f (x) = \frac{x ^{4} - 1}{5}

f (x) = x + 20

f (x) = x + 11

\frac{z}{z - 1}

What is the inverse of f(x)=((x-1)^3)/2-3 ?
The inverse of f(x)=((x-1)^3)/2-3 is \sqrt[3]{2x+6}+1