What is the inverse of f(x)=x^2-x-2 ?

The inverse of f(x)=x^2-x-2 is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2

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inverse of f(x)=x^2-x-2

inverse

f (x) = x^{2} - x - 2

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

Solution steps

y = x^{2} - x - 2

Replace

x

with

y

x = y^{2} - y - 2

Solve for

y, x = y^{2} - y - 2

\frac{1 + 4 x + 9}{2}, \frac{1 - 4 x + 9}{2}

f (x) = \frac{6 x - 1}{x + 4}

f (x) = 1 + 6 + 7 x

\frac{( x - 1 ) ^{2}}{81}

\frac{4}{9 + x}

What is the inverse of f(x)=x^2-x-2 ?
The inverse of f(x)=x^2-x-2 is (1+sqrt(4x+9))/2 ,(1-sqrt(4x+9))/2