What is the inverse of f(x)= 1/2 sqrt(2x+1) ?

The inverse of f(x)= 1/2 sqrt(2x+1) is (4x^2-1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/2 sqrt(2x+1)

inverse

f (x) = \frac{1}{2} 2 x + 1

\frac{4 x ^{2} - 1}{2}

Solution steps

y = \frac{1}{2} 2 x + 1

Replace

x

with

y

x = \frac{1}{2} 2 y + 1

Solve for

y, x = \frac{1}{2} 2 y + 1

\frac{4 x ^{2} - 1}{2}

\frac{1}{x ^{2} - 6 x + 9}

f (x) = y^{2}

f (x) = - \frac{9}{10 x}

4 x + 5

10 e^{2 x}

What is the inverse of f(x)= 1/2 sqrt(2x+1) ?
The inverse of f(x)= 1/2 sqrt(2x+1) is (4x^2-1)/2