What is the inverse of f(x)= 1/4 x^2+1 ?

The inverse of f(x)= 1/4 x^2+1 is 2sqrt(x-1),-2sqrt(x-1)

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inverse of f(x)= 1/4 x^2+1

inverse

f (x) = \frac{1}{4} x^{2} + 1

2 x - 1, - 2 x - 1

Solution steps

y = \frac{1}{4} x^{2} + 1

Replace

x

with

y

x = \frac{1}{4} y^{2} + 1

Solve for

y, x = \frac{1}{4} y^{2} + 1

2 x - 1, - 2 x - 1

f (x) = \frac{3 x}{3 x - 7}

f (x) = \frac{1}{4} ln (x - 2) + 5

f (x) = 5 x + 10

\frac{x + 4}{2 x - 5}

\frac{x + 5}{x + 9}

What is the inverse of f(x)= 1/4 x^2+1 ?
The inverse of f(x)= 1/4 x^2+1 is 2sqrt(x-1),-2sqrt(x-1)