What is the inverse of g(x)=((x-1)^3)/2-3 ?

The inverse of g(x)=((x-1)^3)/2-3 is \sqrt[3]{2x+6}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of g(x)=((x-1)^3)/2-3

inverse

g (x) = \frac{( x - 1 ) ^{3}}{2} - 3

Solution steps

y = \frac{( x - 1 ) ^{3}}{2} - 3

Replace

x

with

y

x = \frac{( y - 1 ) ^{3}}{2} - 3

Solve for

y, x = \frac{( y - 1 ) ^{3}}{2} - 3

f (x) = 3^{x} + 2

6 x - 7

x^{2} - 16

ln (2 - x)

f (x) = 3 x^{- \frac{5}{2}}

What is the inverse of g(x)=((x-1)^3)/2-3 ?
The inverse of g(x)=((x-1)^3)/2-3 is \sqrt[3]{2x+6}+1