What is the inverse of f(x)=(x^2-9)/4 ?

The inverse of f(x)=(x^2-9)/4 is sqrt(4x+9),-sqrt(4x+9)

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inverse of f(x)=(x^2-9)/4

inverse

f (x) = \frac{x ^{2} - 9}{4}

4 x + 9, - 4 x + 9

Solution steps

y = \frac{x ^{2} - 9}{4}

Replace

x

with

y

x = \frac{y ^{2} - 9}{4}

Solve for

y, x = \frac{y ^{2} - 9}{4}

4 x + 9, - 4 x + 9

lo g_{2} (k x - 12)

f (x) = \frac{2 x + 3}{x - 2}

f (x) = \frac{2 x + 3}{7 x + 4}

f (x) = 8 x - 4

f (x) = 2 x + \frac{1}{3}

What is the inverse of f(x)=(x^2-9)/4 ?
The inverse of f(x)=(x^2-9)/4 is sqrt(4x+9),-sqrt(4x+9)