What is the inverse of f(x)=(x+4)^2-3 ?

The inverse of f(x)=(x+4)^2-3 is sqrt(x+3)-4,-sqrt(x+3)-4

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inverse of f(x)=(x+4)^2-3

inverse

f (x) = (x + 4)^{2} - 3

x + 3 - 4, - x + 3 - 4

Solution steps

y = (x + 4)^{2} - 3

Replace

x

with

y

x = (y + 4)^{2} - 3

Solve for

y, x = (y + 4)^{2} - 3

x + 3 - 4, - x + 3 - 4

f (x) = 4 x - 9

f (x) = \frac{5 x - 2}{4 - 5 x}

f (x) = \frac{x}{9 + x ^{2}}

f (x) = 4 - 7 x

f (x) = - 6 x + 8

What is the inverse of f(x)=(x+4)^2-3 ?
The inverse of f(x)=(x+4)^2-3 is sqrt(x+3)-4,-sqrt(x+3)-4