What is the inverse of f(x)=4(x-1)^2 ?

The inverse of f(x)=4(x-1)^2 is (sqrt(x))/2+1,-(sqrt(x))/2+1

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inverse of f(x)=4(x-1)^2

inverse

f (x) = 4 (x - 1)^{2}

\frac{x}{2} + 1, - \frac{x}{2} + 1

Solution steps

y = 4 (x - 1)^{2}

Replace

x

with

y

x = 4 (y - 1)^{2}

Solve for

y, x = 4 (y - 1)^{2}

\frac{x}{2} + 1, - \frac{x}{2} + 1

g (x) = 4 - \frac{3}{2} x

f (x) = (x - 8)^{\frac{1}{4}}

g (x) = 12 x - 1

4 tan (x)

f (x) = 2 + 6 + 8 x

What is the inverse of f(x)=4(x-1)^2 ?
The inverse of f(x)=4(x-1)^2 is (sqrt(x))/2+1,-(sqrt(x))/2+1