What is the inverse of (x^2+5x)^{1/2} ?

The inverse of (x^2+5x)^{1/2} is (-5+(25+4x^2)^{1/2})/2 ,(-5-(25+4x^2)^{1/2})/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (x^2+5x)^{1/2}

inverse

(x^{2} + 5 x)^{\frac{1}{2}}

\frac{- 5 + ( 25 + 4 x ^{2} ) ^{\frac{1}{2}}}{2}, \frac{- 5 - ( 25 + 4 x ^{2} ) ^{\frac{1}{2}}}{2}

Solution steps

y = (x^{2} + 5 x)^{\frac{1}{2}}

Replace

x

with

y

x = (y^{2} + 5 y)^{\frac{1}{2}}

Solve for

y, x = (y^{2} + 5 y)^{\frac{1}{2}}

\frac{- 5 + ( 25 + 4 x ^{2} ) ^{\frac{1}{2}}}{2}, \frac{- 5 - ( 25 + 4 x ^{2} ) ^{\frac{1}{2}}}{2}

f (x) = 1 - 2 + x

f (x) = 5 e^{x - 2} + 6

f (x) = (x + \frac{1}{2})^{2} - \frac{9}{4}

f (x) = \frac{1}{x ^{3} - 4}

f (x) = (\frac{x}{3})^{- \frac{3}{2}}

What is the inverse of (x^2+5x)^{1/2} ?
The inverse of (x^2+5x)^{1/2} is (-5+(25+4x^2)^{1/2})/2 ,(-5-(25+4x^2)^{1/2})/2