What is the inverse of f(x)=2(x+1)^2-3 ?

The inverse of f(x)=2(x+1)^2-3 is sqrt((x+3)/2)-1,-sqrt((x+3)/2)-1

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inverse of f(x)=2(x+1)^2-3

inverse

f (x) = 2 (x + 1)^{2} - 3

\frac{x + 3}{2} - 1, - \frac{x + 3}{2} - 1

Solution steps

y = 2 (x + 1)^{2} - 3

Replace

x

with

y

x = 2 (y + 1)^{2} - 3

Solve for

y, x = 2 (y + 1)^{2} - 3

\frac{x + 3}{2} - 1, - \frac{x + 3}{2} - 1

6 x + 3

y = 3 x^{2}

3 x^{2} - 1

y = x^{\frac{1}{2}} + 4

sin (1)

What is the inverse of f(x)=2(x+1)^2-3 ?
The inverse of f(x)=2(x+1)^2-3 is sqrt((x+3)/2)-1,-sqrt((x+3)/2)-1