What is the inverse of f(x)=1-(sqrt(4-x^2))/2 ?

The inverse of f(x)=1-(sqrt(4-x^2))/2 is 2sqrt(x(-x+2)),-2sqrt(x(-x+2))

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inverse of f(x)=1-(sqrt(4-x^2))/2

inverse

f (x) = 1 - \frac{4 - x ^{2}}{2}

2 x (- x + 2), - 2 x (- x + 2)

Solution steps

y = 1 - \frac{4 - x ^{2}}{2}

Replace

x

with

y

x = 1 - \frac{4 - y ^{2}}{2}

Solve for

y, x = 1 - \frac{4 - y ^{2}}{2}

2 x (- x + 2), - 2 x (- x + 2)

f (x) = \frac{5}{x - 8}

3^{x + 2} - 1

f (x) = \frac{x + 3}{x - 8}

f (x) = 0.1

f (x) = \frac{8 ( x - 2 ) + 5}{3}

What is the inverse of f(x)=1-(sqrt(4-x^2))/2 ?
The inverse of f(x)=1-(sqrt(4-x^2))/2 is 2sqrt(x(-x+2)),-2sqrt(x(-x+2))