What is the inverse of f(x)=\sqrt[3]{x}-7 ?

The inverse of f(x)=\sqrt[3]{x}-7 is x^3+21x^2+147x+343

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inverse of f(x)=\sqrt[3]{x}-7

inverse

f (x) = 3 x - 7

x^{3} + 21 x^{2} + 147 x + 343

Solution steps

y = 3 x - 7

Replace

x

with

y

x = 3 y - 7

Solve for

y, x = 3 y - 7

x^{3} + 21 x^{2} + 147 x + 343

g (x) = \frac{x + 1}{2}

f (x) = x^{2} + 10 x + 15

f (x) = \frac{x ^{2} - 9}{2}

f (x) = (x - 17)^{2}

9 x - 3

What is the inverse of f(x)=\sqrt[3]{x}-7 ?
The inverse of f(x)=\sqrt[3]{x}-7 is x^3+21x^2+147x+343