What is the inverse of f(x)=11-8x-x^2 ?

The inverse of f(x)=11-8x-x^2 is -4-sqrt(-x+27),-4+sqrt(-x+27)

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inverse of f(x)=11-8x-x^2

inverse

f (x) = 11 - 8 x - x^{2}

- 4 - - x + 27, - 4 + - x + 27

Solution steps

y = 11 - 8 x - x^{2}

Replace

x

with

y

x = 11 - 8 y - y^{2}

Solve for

y, x = 11 - 8 y - y^{2}

- 4 - - x + 27, - 4 + - x + 27

f (x) = x^{2} - 4 x + 5, x \geq 3

f (x) = y + 4 x - 5 = 0

f (x) = x^{\frac{1}{4}}

f (x) = \frac{( x + 9 ) ^{\frac{1}{5}}}{10}

f (x) = - \frac{1}{2} x - 1

What is the inverse of f(x)=11-8x-x^2 ?
The inverse of f(x)=11-8x-x^2 is -4-sqrt(-x+27),-4+sqrt(-x+27)