What is the inverse of f(x)= 1/((x-4)(x+4)) ?

The inverse of f(x)= 1/((x-4)(x+4)) is (sqrt(-x(-16x-1)))/x ,-(sqrt(-x(-16x-1)))/x

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inverse of f(x)= 1/((x-4)(x+4))

inverse

f (x) = \frac{1}{( x - 4 ) ( x + 4 )}

\frac{- x ( - 16 x - 1 )}{x}, - \frac{- x ( - 16 x - 1 )}{x}

Solution steps

y = \frac{1}{( x - 4 ) ( x + 4 )}

Replace

x

with

y

x = \frac{1}{( y - 4 ) ( y + 4 )}

Solve for

y, x = \frac{1}{( y - 4 ) ( y + 4 )}

\frac{- x ( - 16 x - 1 )}{x}, - \frac{- x ( - 16 x - 1 )}{x}

y = lo g_{10} (x + 9)

f (x) = (1 - x^{3})^{\frac{1}{5}} + 2

f (x) = \frac{lo g _{10} ( x - 5 )}{2}

f (x) = ln (x - 2) + 3

f (x) = \frac{7 x + 2}{x - 9}

What is the inverse of f(x)= 1/((x-4)(x+4)) ?
The inverse of f(x)= 1/((x-4)(x+4)) is (sqrt(-x(-16x-1)))/x ,-(sqrt(-x(-16x-1)))/x