What is the inverse of sqrt(25-x^2) ?

The inverse of sqrt(25-x^2) is sqrt(-x^2+25),-sqrt(-x^2+25)

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inverse of sqrt(25-x^2)

inverse

25 - x^{2}

- x^{2} + 25, - - x^{2} + 25

Solution steps

y = 25 - x^{2}

Replace

x

with

y

x = 25 - y^{2}

Solve for

y, x = 25 - y^{2}

- x^{2} + 25, - - x^{2} + 25

f (x) = \frac{7}{7 - 5 x}

f (x) = \frac{1}{3} lo g_{2} (x) + 1

x^{2} - x - 2

f (x) = 2 ln (x)

f (x) = \frac{1}{2} x + 1

What is the inverse of sqrt(25-x^2) ?
The inverse of sqrt(25-x^2) is sqrt(-x^2+25),-sqrt(-x^2+25)