What is the inverse of f(x)=(x^3+2)/(x^3-2) ?

The inverse of f(x)=(x^3+2)/(x^3-2) is cube root of (2+2x)/(x-1)

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inverse of f(x)=(x^3+2)/(x^3-2)

inverse

f (x) = \frac{x ^{3} + 2}{x ^{3} - 2}

Solution steps

y = \frac{x ^{3} + 2}{x ^{3} - 2}

Replace

x

with

y

x = \frac{y ^{3} + 2}{y ^{3} - 2}

Solve for

y, x = \frac{y ^{3} + 2}{y ^{3} - 2}

f (x) = \frac{2}{2 x - 1}

y = \frac{x + 1}{2 x + 1}

f (x) = - 5 x - 30

\frac{e ^{x}}{1 + e ^{x}}

f (x) = (x - 9)^{2}, x \geq 9

What is the inverse of f(x)=(x^3+2)/(x^3-2) ?
The inverse of f(x)=(x^3+2)/(x^3-2) is cube root of (2+2x)/(x-1)