What is the inverse of f(x)=2x^2-3x-1 ?

The inverse of f(x)=2x^2-3x-1 is (3+sqrt(8x+17))/4 ,(3-sqrt(8x+17))/4

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inverse of f(x)=2x^2-3x-1

inverse

f (x) = 2 x^{2} - 3 x - 1

\frac{3 + 8 x + 17}{4}, \frac{3 - 8 x + 17}{4}

Solution steps

y = 2 x^{2} - 3 x - 1

Replace

x

with

y

x = 2 y^{2} - 3 y - 1

Solve for

y, x = 2 y^{2} - 3 y - 1

\frac{3 + 8 x + 17}{4}, \frac{3 - 8 x + 17}{4}

e^{x} - 3

f (x) = \frac{x}{2 x ^{2} - x - 1}

f (x) = 2 x^{2} - 6 x + 13

4 x - 4

f (x) = \frac{4 x}{2 x + 1}

What is the inverse of f(x)=2x^2-3x-1 ?
The inverse of f(x)=2x^2-3x-1 is (3+sqrt(8x+17))/4 ,(3-sqrt(8x+17))/4