What is the inverse of (x^2+6x)^{1/2} ?

The inverse of (x^2+6x)^{1/2} is -3+(x^2+9)^{1/2},-(x^2+9)^{1/2}-3

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inverse of (x^2+6x)^{1/2}

inverse

(x^{2} + 6 x)^{\frac{1}{2}}

- 3 + (x^{2} + 9)^{\frac{1}{2}}, - (x^{2} + 9)^{\frac{1}{2}} - 3

Solution steps

y = (x^{2} + 6 x)^{\frac{1}{2}}

Replace

x

with

y

x = (y^{2} + 6 y)^{\frac{1}{2}}

Solve for

y, x = (y^{2} + 6 y)^{\frac{1}{2}}

- 3 + (x^{2} + 9)^{\frac{1}{2}}, - (x^{2} + 9)^{\frac{1}{2}} - 3

f (x) = \frac{( 4 x + 3 )}{( 2 x + 5 )}

f (x) = ln (\frac{2 x}{1 - x ^{2}})

\frac{x ^{3} - 27}{x - 3}

y = - 3 x - 4

What is the inverse of (x^2+6x)^{1/2} ?
The inverse of (x^2+6x)^{1/2} is -3+(x^2+9)^{1/2},-(x^2+9)^{1/2}-3