What is the inverse of f(x)=(x^{1/3})/6+7 ?

The inverse of f(x)=(x^{1/3})/6+7 is 216x^3-4536x^2+31752x-74088

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inverse of f(x)=(x^{1/3})/6+7

inverse

f (x) = \frac{x ^{\frac{1}{3}}}{6} + 7

216 x^{3} - 4536 x^{2} + 31752 x - 74088

Solution steps

y = \frac{x ^{\frac{1}{3}}}{6} + 7

Replace

x

with

y

x = \frac{y ^{\frac{1}{3}}}{6} + 7

Solve for

y, x = \frac{y ^{\frac{1}{3}}}{6} + 7

216 x^{3} - 4536 x^{2} + 31752 x - 74088

f (x) = 1 - ln (3 x)

\frac{7 x + 3}{3 x - 7}

f (x) = (3 x - 1)^{3}

f (x) = a^{3} + 5

What is the inverse of f(x)=(x^{1/3})/6+7 ?
The inverse of f(x)=(x^{1/3})/6+7 is 216x^3-4536x^2+31752x-74088