What is the inverse of f(x)=x^2+8x-9 ?

The inverse of f(x)=x^2+8x-9 is -4+sqrt(x+25),-sqrt(x+25)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2+8x-9

inverse

f (x) = x^{2} + 8 x - 9

- 4 + x + 25, - x + 25 - 4

Solution steps

y = x^{2} + 8 x - 9

Replace

x

with

y

x = y^{2} + 8 y - 9

Solve for

y, x = y^{2} + 8 y - 9

- 4 + x + 25, - x + 25 - 4

f (x) = \frac{1}{2} (e^{x} - e^{- x})

cos (x - π) + 2

f (x) = \frac{e ^{x} + 1}{e ^{x} - 1}

f (x) = (\frac{x ^{5}}{10})^{\frac{1}{7}}

f (n) = n + 1

What is the inverse of f(x)=x^2+8x-9 ?
The inverse of f(x)=x^2+8x-9 is -4+sqrt(x+25),-sqrt(x+25)-4