What is the (f(x)\circ g(x)),f(x)=x^2,g(x)=x+1 ?

The (f(x)\circ g(x)),f(x)=x^2,g(x)=x+1 is x^2+2x+1

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(f(x)\circ g(x)),f(x)=x^2,g(x)=x+1

(f (x) \circ g (x)), f (x) = x^{2}, g (x) = x + 1

x^{2} + 2 x + 1

Solution steps

Find

(f \circ g)

given

f (x) = x^{2}, g (x) = x + 1

f \circ g = f (g (x))

g (x) = x + 1

= f (x + 1)

f (x + 1) : (x + 1)^{2}

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + 2 x + 1

f (x) = 4 x + 1

8 x^{4}

\frac{3 x ^{3} + 4 x + 5}{2 x ^{3} + 3 x - 5}

f (x) = x^{2} - 6 x + 8

\frac{- x ^{2}}{x ^{2} + 4}

What is the (f(x)\circ g(x)),f(x)=x^2,g(x)=x+1 ?
The (f(x)\circ g(x)),f(x)=x^2,g(x)=x+1 is x^2+2x+1