What is the inverse of f(x)=-1/2 (x-1)^2+8 ?

The inverse of f(x)=-1/2 (x-1)^2+8 is sqrt(-2x+16)+1,-sqrt(-2x+16)+1

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inverse of f(x)=-1/2 (x-1)^2+8

inverse

f (x) = - \frac{1}{2} (x - 1)^{2} + 8

- 2 x + 16 + 1, - - 2 x + 16 + 1

Solution steps

y = - \frac{1}{2} (x - 1)^{2} + 8

Replace

x

with

y

x = - \frac{1}{2} (y - 1)^{2} + 8

Solve for

y, x = - \frac{1}{2} (y - 1)^{2} + 8

- 2 x + 16 + 1, - - 2 x + 16 + 1

f (x) = x - 3 + 4

f (x) = - 3 x + 14

f (x) = 3 x (4 - x)

f (x) = ln (2 + e^{x - 3})

f (x) = 8 x^{7} - 5

What is the inverse of f(x)=-1/2 (x-1)^2+8 ?
The inverse of f(x)=-1/2 (x-1)^2+8 is sqrt(-2x+16)+1,-sqrt(-2x+16)+1