What is the inverse of f(x)=(x^{1/5}-7)^7 ?

The inverse of f(x)=(x^{1/5}-7)^7 is x^{5/7}+35x^{4/7}+490x^{3/7}+3430x^{2/7}+12005\sqrt[7]{x}+16807

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inverse of f(x)=(x^{1/5}-7)^7

inverse

f (x) = (x^{\frac{1}{5}} - 7)^{7}

Solution steps

y = (x^{\frac{1}{5}} - 7)^{7}

Replace

x

with

y

x = (y^{\frac{1}{5}} - 7)^{7}

Solve for

y, x = (y^{\frac{1}{5}} - 7)^{7}

f (x) = \frac{x}{2 x - 6}

g (x) = lo g_{3} (x)

f (x) = x - 4 + 2

f (x) = - 8 x + 24

f (x) = 2 e^{3 x} - 3

What is the inverse of f(x)=(x^{1/5}-7)^7 ?
The inverse of f(x)=(x^{1/5}-7)^7 is x^{5/7}+35x^{4/7}+490x^{3/7}+3430x^{2/7}+12005\sqrt[7]{x}+16807