What is the inverse of f(x)=3(x-2)^2-3 ?

The inverse of f(x)=3(x-2)^2-3 is sqrt((x+3)/3)+2,-sqrt((x+3)/3)+2

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inverse of f(x)=3(x-2)^2-3

inverse

f (x) = 3 (x - 2)^{2} - 3

\frac{x + 3}{3} + 2, - \frac{x + 3}{3} + 2

Solution steps

y = 3 (x - 2)^{2} - 3

Replace

x

with

y

x = 3 (y - 2)^{2} - 3

Solve for

y, x = 3 (y - 2)^{2} - 3

\frac{x + 3}{3} + 2, - \frac{x + 3}{3} + 2

\frac{1}{x + 1} + 2

f (x) = \frac{3}{5} - \frac{3}{10} x

f (x) = 2 - 3 x^{2}

f (x) = \frac{x ^{\frac{1}{3}}}{4}

f (x) = - 5 x + 5

What is the inverse of f(x)=3(x-2)^2-3 ?
The inverse of f(x)=3(x-2)^2-3 is sqrt((x+3)/3)+2,-sqrt((x+3)/3)+2