What is the inverse of (e^y-e^{-y})/2 ?

The inverse of (e^y-e^{-y})/2 is ln(y+sqrt(y^2+1)),ln(y-sqrt(y^2+1))

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inverse of (e^y-e^{-y})/2

inverse

\frac{e ^{y} - e ^{- y}}{2}

ln (y + y^{2} + 1), ln (y - y^{2} + 1)

Solution steps

y = \frac{e ^{y} - e ^{- y}}{2}

Replace

y

with

y

y = \frac{e ^{y} - e ^{- y}}{2}

Solve for

y, y = \frac{e ^{y} - e ^{- y}}{2}

ln (y + y^{2} + 1), ln (y - y^{2} + 1)

4 x + 4

f (x) = \frac{2}{x + 7}

f (x) = x + 2 + 3

x^{4} - x^{2}

What is the inverse of (e^y-e^{-y})/2 ?
The inverse of (e^y-e^{-y})/2 is ln(y+sqrt(y^2+1)),ln(y-sqrt(y^2+1))