What is the inverse of f(x)=x^2+18x+81 ?

The inverse of f(x)=x^2+18x+81 is -9+sqrt(x),-sqrt(x)-9

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inverse of f(x)=x^2+18x+81

inverse

f (x) = x^{2} + 18 x + 81

- 9 + x, - x - 9

Solution steps

y = x^{2} + 18 x + 81

Replace

x

with

y

x = y^{2} + 18 y + 81

Solve for

y, x = y^{2} + 18 y + 81

- 9 + x, - x - 9

arccos (1)

y = \frac{3 x + 1}{2}

f (x) = \frac{( 3 - 8 x )}{( 4 + 7 x )}

f (x) = \frac{3 x - 2}{7}

f (x) = \frac{3 x - 2}{2}

What is the inverse of f(x)=x^2+18x+81 ?
The inverse of f(x)=x^2+18x+81 is -9+sqrt(x),-sqrt(x)-9