What is the inverse of f(x)=(x-2)^2-3 ?

The inverse of f(x)=(x-2)^2-3 is sqrt(x+3)+2,-sqrt(x+3)+2

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inverse of f(x)=(x-2)^2-3

inverse

f (x) = (x - 2)^{2} - 3

x + 3 + 2, - x + 3 + 2

Solution steps

y = (x - 2)^{2} - 3

Replace

x

with

y

x = (y - 2)^{2} - 3

Solve for

y, x = (y - 2)^{2} - 3

x + 3 + 2, - x + 3 + 2

x^{2} + 4 x + 3

f (5) = ln (3 x - 5) - ln (x + 9) + 5

f (x) = x^{2} + x, x \geq \frac{1}{2}

7 x + 4

g (x) = \frac{x - 4}{2 x + 3}

What is the inverse of f(x)=(x-2)^2-3 ?
The inverse of f(x)=(x-2)^2-3 is sqrt(x+3)+2,-sqrt(x+3)+2