What is the inverse of 7x+sqrt(x+50) ?

The inverse of 7x+sqrt(x+50) is (14x+1+sqrt(28x+9801))/(98),(14x+1-sqrt(28x+9801))/(98)

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inverse of 7x+sqrt(x+50)

inverse

7 x + x + 50

\frac{14 x + 1 + 28 x + 9801}{98}, \frac{14 x + 1 - 28 x + 9801}{98}

Solution steps

y = 7 x + x + 50

Replace

x

with

y

x = 7 y + y + 50

Solve for

y, x = 7 y + y + 50

\frac{14 x + 1 + 28 x + 9801}{98}, \frac{14 x + 1 - 28 x + 9801}{98}

2 x^{2} + 1

x^{2} - 4 x + 4

f (x) = - 2 e^{- x} + 3

f (x) = arcsin (\frac{1}{2})

\frac{7 x + 2}{x - 2}

What is the inverse of 7x+sqrt(x+50) ?
The inverse of 7x+sqrt(x+50) is (14x+1+sqrt(28x+9801))/(98),(14x+1-sqrt(28x+9801))/(98)