What is the inverse of f(x)= 1/(sqrt(x^2+x-12)) ?

The inverse of f(x)= 1/(sqrt(x^2+x-12)) is (-x+sqrt(49x^2+4))/(2x),-(x+sqrt(49x^2+4))/(2x)

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inverse of f(x)= 1/(sqrt(x^2+x-12))

inverse

f (x) = \frac{1}{x ^{2} + x - 12}

\frac{- x + 49 x ^{2} + 4}{2 x}, - \frac{x + 49 x ^{2} + 4}{2 x}

Solution steps

y = \frac{1}{x ^{2} + x - 12}

Replace

x

with

y

x = \frac{1}{y ^{2} + y - 12}

Solve for

y, x = \frac{1}{y ^{2} + y - 12}

\frac{- x + 49 x ^{2} + 4}{2 x}, - \frac{x + 49 x ^{2} + 4}{2 x}

f (x) = \frac{x + 5}{7}

\frac{2}{3 x - 5}

h (x) = \frac{8 - x ^{2}}{5}

f (x) = \frac{1}{x ^{3} + 2}

f (x) = \frac{x + 6}{4}

What is the inverse of f(x)= 1/(sqrt(x^2+x-12)) ?
The inverse of f(x)= 1/(sqrt(x^2+x-12)) is (-x+sqrt(49x^2+4))/(2x),-(x+sqrt(49x^2+4))/(2x)