What is the inverse of f(x)= 1/(1-x^2) ?

The inverse of f(x)= 1/(1-x^2) is sqrt(-(1-x)/x),-sqrt(-(1-x)/x)

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inverse of f(x)= 1/(1-x^2)

inverse

f (x) = \frac{1}{1 - x ^{2}}

- \frac{1 - x}{x}, - - \frac{1 - x}{x}

Solution steps

y = \frac{1}{1 - x ^{2}}

Replace

x

with

y

x = \frac{1}{1 - y ^{2}}

Solve for

y, x = \frac{1}{1 - y ^{2}}

- \frac{1 - x}{x}, - - \frac{1 - x}{x}

f (x) = \frac{x + 1}{3 - x}

x^{2} - 20 x + 100

f (x) = \frac{2 x}{9 + 2 x}

f (x) = \frac{2}{x} + 5

f (x) = 1 - e^{x}

What is the inverse of f(x)= 1/(1-x^2) ?
The inverse of f(x)= 1/(1-x^2) is sqrt(-(1-x)/x),-sqrt(-(1-x)/x)