What is the inverse of 2*3^x+9^x+5 ?

The inverse of 2*3^x+9^x+5 is (ln(-1+sqrt(x-4)))/(ln(3)),(ln(-sqrt(x-4)-1))/(ln(3))

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inverse of 2*3^x+9^x+5

inverse

2 \cdot 3^{x} + 9^{x} + 5

\frac{ln ( - 1 + x - 4 )}{ln ( 3 )}, \frac{ln ( - x - 4 - 1 )}{ln ( 3 )}

Solution steps

y = 2 \cdot 3^{x} + 9^{x} + 5

Replace

x

with

y

x = 2 \cdot 3^{y} + 9^{y} + 5

Solve for

y, x = 2 \cdot 3^{y} + 9^{y} + 5

\frac{ln ( - 1 + x - 4 )}{ln ( 3 )}, \frac{ln ( - x - 4 - 1 )}{ln ( 3 )}

- 2 + ln (x)

h (c) = 2 c + 2

f (x) = \frac{x ^{5} + 4}{3}

f (x) = 5 + (2 x + 6)^{3}

4 x^{3} - 9

What is the inverse of 2*3^x+9^x+5 ?
The inverse of 2*3^x+9^x+5 is (ln(-1+sqrt(x-4)))/(ln(3)),(ln(-sqrt(x-4)-1))/(ln(3))