What is the inverse of f(x)=-sqrt(9-x^2) ?

The inverse of f(x)=-sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)

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inverse of f(x)=-sqrt(9-x^2)

inverse

f (x) = - 9 - x^{2}

- x^{2} + 9, - - x^{2} + 9

Solution steps

y = - 9 - x^{2}

Replace

x

with

y

x = - 9 - y^{2}

Solve for

y, x = - 9 - y^{2}

- x^{2} + 9, - - x^{2} + 9

f (x) = x + x + 2

f (x) = \frac{2 x}{( 2 x ) ^{2} - 2 x - 2}

y = \frac{1}{3} x + 4

\frac{x - 7}{2}

What is the inverse of f(x)=-sqrt(9-x^2) ?
The inverse of f(x)=-sqrt(9-x^2) is sqrt(-x^2+9),-sqrt(-x^2+9)