What is the inverse of f(x)= 2/(sqrt(y^3+5)) ?

The inverse of f(x)= 2/(sqrt(y^3+5)) is cube root of (4-5y^2)/(y^2)

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inverse of f(x)= 2/(sqrt(y^3+5))

inverse

f (x) = \frac{2}{y ^{3} + 5}

Solution steps

x = \frac{2}{y ^{3} + 5}

Replace

y

with

x

y = \frac{2}{x ^{3} + 5}

Solve for

x, y = \frac{2}{x ^{3} + 5}

tan (\frac{1}{3})

f (x) = (x - 10)^{3} + 4

f (x) = 3 (x - 5)

f (x) = \frac{1}{2} x + \frac{5}{2}

f (x) = \frac{5 x}{9 x - 1}

What is the inverse of f(x)= 2/(sqrt(y^3+5)) ?
The inverse of f(x)= 2/(sqrt(y^3+5)) is cube root of (4-5y^2)/(y^2)